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x^2-600x+20000=0
a = 1; b = -600; c = +20000;
Δ = b2-4ac
Δ = -6002-4·1·20000
Δ = 280000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{280000}=\sqrt{40000*7}=\sqrt{40000}*\sqrt{7}=200\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-200\sqrt{7}}{2*1}=\frac{600-200\sqrt{7}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+200\sqrt{7}}{2*1}=\frac{600+200\sqrt{7}}{2} $
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